------------------------------------------------------------------------
-- Some examples related to a "linear or affine types" modality
-- without a dedicated nr function
------------------------------------------------------------------------

open import Graded.Modality.Instances.Linear-or-affine
open import Graded.Usage.Restrictions
open import Graded.Mode
import Graded.Mode.Instances.Zero-one
open import Graded.Mode.Instances.Zero-one.Variant linear-or-affine

module Graded.Modality.Instances.Linear-or-affine.Examples.Bad.No-nr
  {variant : Mode-variant}
  (open Graded.Mode.Instances.Zero-one variant)
  (UR : Usage-restrictions linear-or-affine Zero-one-isMode)
  (open Usage-restrictions UR)
  -- There is no dedicated nr function.
   no-nr : Nr-not-available 
  where

open Mode-variant variant

open import Tools.Bool using (T)
open import Tools.Empty
open import Tools.Function
open import Tools.Product
open import Tools.PropositionalEquality
import Tools.Reasoning.PartialOrder
open import Tools.Relation

open import Graded.Modality Linear-or-affine

private
  module M = Modality linear-or-affine

open import Graded.Context linear-or-affine
open import Graded.Context.Properties linear-or-affine
open import Graded.Modality.Properties linear-or-affine
open import Graded.Usage UR
open import Graded.Usage.Inversion UR
open import Graded.Usage.Properties.Zero-one variant UR

open import Definition.Untyped.Nat linear-or-affine

-- The term double is well-resourced (even though it can be given a
-- linear type) if and only if 𝟘ᵐ is not allowed.

▸double : (¬ T 𝟘ᵐ-allowed)  ε ▸[ 𝟙ᵐ ] double
▸double =
    (let open Tools.Reasoning.PartialOrder ≤ᶜ-poset in
     λ not-ok 
       lamₘ $
       natrec-no-nrₘ₀₁ var (sucₘ var) var
         (sub ℕₘ $ begin
            𝟘ᶜ   𝟘ᵐ?  · 𝟘  ≈⟨ ≈ᶜ-refl  M.·-zeroʳ  𝟘ᵐ?  
            𝟘ᶜ                )
         ≤ᶜ-refl
         (⊥-elim ∘→ not-ok)
         ≤ᶜ-refl
         ≤ᶜ-refl)
  , (let open Tools.Reasoning.PartialOrder ≤-poset in
     λ ▸λ+ ok 
       case inv-usage-lam ▸λ+ of λ {
         (invUsageLam ▸+ _) 
       case inv-usage-natrec-no-nr₀₁ ▸+ of λ {
         (_ , _  p , _  q , _ , _  r , _ , _ , _ , _
            , _  𝟙≤r , _ , r≤₁ , _ , _  r≤₂) 
       case r≤₁ ok of λ {
         (_  r≤₁) 
       case lemma p $ begin
         𝟙                  ≤⟨ 𝟙≤r 
         r                  ≤⟨ r≤₂ 
         p + 𝟘 · q + 𝟙 · r  ≡⟨ cong (p +_) $
                               trans (cong₂ _+_ (M.·-zeroˡ q) (M.·-identityˡ _)) $
                               trans (M.+-identityˡ _) $
                               𝟙-maximal 𝟙≤r 
         p + 𝟙              
       of λ {
         p≡𝟘 
       case begin
         𝟙  ≤⟨ 𝟙≤r 
         r  ≤⟨ r≤₁ 
         p  ≡⟨ p≡𝟘 
         𝟘  
       of λ () }}}})
  where
  lemma :  p  𝟙  p + 𝟙  p  𝟘
  lemma 𝟘  refl = refl
  lemma 𝟙  ()
  lemma ≤𝟙 ()
  lemma ≤ω ()

-- The term plus is not well-resourced.

¬▸plus : ¬ ε ▸[ 𝟙ᵐ ] plus
¬▸plus ▸λλ+ =
  case inv-usage-lam ▸λλ+ of λ {
    (invUsageLam ▸λ+ _) 
  case inv-usage-lam ▸λ+ of λ {
    (invUsageLam {δ = _  ≤ω} _  (_  ()));
    (invUsageLam {δ = _  𝟘}  _  (_  ()));
    (invUsageLam {δ = _  ≤𝟙} _  (_  ()));
    (invUsageLam {δ = _  𝟙}  ▸+ _) 
  case inv-usage-natrec-no-nr ▸+ of λ {
    (_  p  _ , _ , _ , _ , _  q  _ , ▸x0 , _ , _ , _
               , _  𝟙≤q  _ , _  q≤p  _ , _) 
  case inv-usage-var ▸x0 of λ {
    (_  p≤𝟘  _) 
  case begin
    𝟙  ≤⟨ 𝟙≤q 
    q  ≤⟨ q≤p 
    p  ≤⟨ p≤𝟘 
    𝟘  
  of λ () }}}}
  where
  open Tools.Reasoning.PartialOrder ≤-poset